A particle moves in a circular path such that its speed v varies with distance as v= alpha sqrt(s) where alpha is a positive constant. Find the acceleration of particle after trafversing a distance S?

A particle moves in a circular path such that its speed v varies with

1.	A particle moves in a circular path such that its speed v varies with distance as v= alpha sqrt(s) where alpha is a positive constant. Find the acceleration of particle after trafversing a distance S?
Answer» `ALPHA SQRT(1/4 - (S^2)/(R^2))` `alpha sqrt(1/4 + (S^2)/(R^2))` `alpha sqrt(1/2 + (S^2)/(R^2))` `alpha^2 sqrt(1/2 + (S^2)/(R^2))` ANSWER :B

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A particle moves in a circular path such that its speed v varies with distance as v= alpha sqrt(s) where alpha is a positive constant. Find the acceleration of particle after trafversing a distance S?

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