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A particle moves in a particle of radius `0.5 m` at a speed that uniformly increases. Find the angular acceleration of particle if its speed changes from `2.0m//s` to `4.0 m//s` in `4.0s`

Answer» Correct Answer - A::B::D
The tangential acceleration of the particle is
`a_(t)=(dv)/(dt) =(4.0-2.0)/4.0=0.5 m//s^(2)`
The angular acceleration is `alpha=(a_(t))/r=0.5/0.5=1 rad//s^(2)`


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