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A particle moves in a straight line and its velocity v at time t seconds is given byv = 3t^2 – 4t + 5 cm/second. What will be the acceleration of the particle during first 3 seconds after the start?(a) 10cm/sec^2(b) 12cm/sec^2(c) 14cm/sec^2(d) 16cm/sec^2This question was posed to me in unit test.Question is from Calculus Application topic in division Application of Calculus of Mathematics – Class 12 |
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Answer» The CORRECT CHOICE is (c) 14cm/sec^2 |
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