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InterviewSolution
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A particle moves in a straight-line OA; the distance of the particle from O at time t seconds is x ft, where x = a + bt + ct^2 (a, b > 0). What is the meaning of the constant c?(a) Uniform acceleration(b) Non – uniform acceleration(c) Uniform retardation(d) Non – uniform retardationI got this question during an interview.The question is from Calculus Application in section Application of Calculus of Mathematics – Class 12 |
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Answer» CORRECT answer is (a) Uniform acceleration For explanation: We have, x = a + BT + ct^2……….(1) LET, v and f be the velocity and acceleration of a particle at time t seconds. Then, v = dx/dt = d(a + bt + ct^2)/dt= B + ct……….(2) And f = dv/dt = d(b + ct)/dt = c……….(3) Since f = dv/dt = c, hence, c represents the uniform acceleration of the particle. |
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