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A particle moves in a straight line with a constant acceleration. It changes its velocity from `10 ms^-1` to `20 ms^-1` while passing through a distance `135 m` in `t` seconds. The value of `t` is.A. 12B. 9C. 10D. 1.8 |
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Answer» Correct Answer - B For constant acceleration `v^(2)=u^(2)+2as` `(20)^(2)=(10)^(2)+2xxaxx135` `a=(300)/(270)ms^(-2)` As `v=u+at` `20=10+axxt` 10 = at `10=(300)/(270)xxt` ltbtgt t = 9 sec |
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