Saved Bookmarks
| 1. |
A particle moves in X-Y plane under the action of forces F such that the values of linear momentum ‘p’ at any time is p_(x) =2 cos t and p_(y) = 2 sin t. The angle betweenvec(F) and vec(p) at the time t will be : |
|
Answer» <P>0° Now `vec(F)=(dvecp)/(t)=-2sinthati+2costhatj`. The angle will be `costheta=(vec(F).vec(p))/(Fp)` `costheta=(-4sintcost + 4sintcost)/(Fxxp)` `theta=90^@` |
|