A particle moves in X-Y plane under the action of forces F such that the values of linear momentum 'p' at any times is p_(x) = 2 cos t and p_(y) = 2 sin t . The angle between vec(F) and at the time t will be:

A particle moves in X-Y plane under the action of forces F such that t

1.	A particle moves in X-Y plane under the action of forces F such that the values of linear momentum 'p' at any times is p_(x) = 2 cos t and p_(y) = 2 sin t . The angle between vec(F) and at the time t will be:
Answer» <P>`0^@` `30^@` `90^@` `180^@` Solution :Here `VEC(p)=vec(p_(x))hati + vec(p_(y))hatj=2costhati + 2sinthatj`

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A particle moves in X-Y plane under the action of forces F such that the values of linear momentum 'p' at any times is p_(x) = 2 cos t and p_(y) = 2 sin t . The angle between vec(F) and at the time t will be:

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