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A particle moves move on the rough horizontal ground with some initial velocity `V_(0)`. If `(3)/(4)` of its kinetic enegry lost due to friction in time `t_(0)`. The coefficient of friction between the particle and the ground is.A. `(v_(0))/(2g t_(0))`B. `(v_(0))/(4g t_(0))`C. `(3v_(0))/(4g t_(0))`D. `(v_(0))/(g t_(0))` |
Answer» Correct Answer - A |
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