A particle moves under the force `F(x) = (x^(2) - 6x)N`, where `x` is in metres. For small displacements from the origin what is the force constant in the simple harmonic motion approximation ?

A particle moves under the force `F(x) = (x^(2) - 6x)N`, where `x` is

1.	A particle moves under the force `F(x) = (x^(2) - 6x)N`, where `x` is in metres. For small displacements from the origin what is the force constant in the simple harmonic motion approximation ?
Answer» For small values of `x`, the term `x^(2)` can be neglected. `:. F = -6x` Comparing with `F = -kx`, we get `k = 6N//m`

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A particle moves under the force `F(x) = (x^(2) - 6x)N`, where `x` is in metres. For small displacements from the origin what is the force constant in the simple harmonic motion approximation ?

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