1.

A particle movesin a circular path such that its speed v varies with distance as v=alphasqrts where alpha is a positive constant. Find the acceleration of particle after traversing a distance S?

Answer»

`ALPHA^(2)SQRT((1)/(4)-(S^(2))/(R^(2)))`
`alpha^(2)sqrt((1)/(4)+(S^(2))/(R^(2)))`
`alphasqrt((1)/(2)+(S^(2))/(R^(2)))`
`alpha^(2)sqrt((1)/(2)+(S^(2))/(R^(2)))`

Answer :B


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