1.

A particle moving in straight line cover half the distance with speed 3 ms^-1. The other half is covered in two equal time intervals with speed 4.5 ms^-1 and 7.5 ms^-1 respectively. The average speed of the particle during motion is

Answer»

`4 ms^(-1)`
`5MS^(-1)`
`5.5 ms^(-1)`
`4.5ms^(-1)`

Solution :Time taken to cover OA`=((X/2))/(3)=(x)/(6)`

Since AB and BC are COVERED in EQUAL time intervels say `t_2`
`:. 4.5 t_(2)+7.5t_(2)=(x)/(2)implies t_(2)=(x)/(24)`
`:.` TOTAL time taken, `t=(x)/(6)+(x)/(24)+(x)/(24)=(x)/(4)`.
`:.` Average speed =`(x)/(x//4)=4 m//s`


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