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A particle moving on x - axis has potential energy `U = 2 - 20x + 5x^(2)` joule along x - axis. The particle is relesed at `x = -3`. The maximum value of `x` will be (`x` is in metre)A. `5m`B. `3 m`C. `7 m`D. `8 m` |
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Answer» Correct Answer - C `F = - (dU)/(dx) = 20 - 10x` `F = 0` at `x = 0` So, from `x = - 3` to `x = 2`, amplitude in `5`. Hence, other extreme position will be `x = 2 + 5 = 7` |
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