1.

A particle of charge per unit mass α is releasedfrom origin with a velocity v=vo, in a uniformmagnetic field B-B,k. If the particle passesthrough (0, y, 0) then y is equal to2v0(2)(3)(4)ΒοαΒα

Answer»

we know that in this case

y =2r

where 'r' is the radius of the circular path of the charged particle

now, we know that

F = mv2/r = qvB

or

r = mv/ qB

or

r =v/ [(q/m).B]

we know that a = q/m , so

r =v/ aB

also, in scalar form

v = v0

B = B0

so,

r = v0/ aB0

thus,

y = 2r

or

y = 2v0/ aB0

hence, Correct answer: 2* v not / B not * aoption (c)



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