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A particle of charge per unit mass α is releasedfrom origin with a velocity v=vo, in a uniformmagnetic field B-B,k. If the particle passesthrough (0, y, 0) then y is equal to2v0(2)(3)(4)ΒοαΒα |
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Answer» we know that in this case y =2r where 'r' is the radius of the circular path of the charged particle now, we know that F = mv2/r = qvB or r = mv/ qB or r =v/ [(q/m).B] we know that a = q/m , so r =v/ aB also, in scalar form v = v0 B = B0 so, r = v0/ aB0 thus, y = 2r or y = 2v0/ aB0 hence, Correct answer: 2* v not / B not * aoption (c) |
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