InterviewSolution
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InterviewSolution
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A particle of charge `q` and mass `m` moves in a circular orbit of radius `r` with angular speed `omega`. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends onA. `q//m`B. `2q//m`C. `q//2m`D. `q^2//2m` |
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Answer» Correct Answer - C Magnetic moment is given by , `M=IA=(q)/(T) pi r^2=(2pi)/(T)(qr^2)/(2)=(omega qr^2)/(2)` Angular momentum `=L=I omega=mr^2omega` `therefore (M)/(L)=(omegaq r^2//2)/(mr^2omega)=(q)/(2m)`. |
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