1.

A particle of mass 0.01 kg moving horizontally with velocity 20 m/s strikes a stationary wedge ABC of mass 0.05 kg with a velocity of 20 m/s near the apex of the wedge is free to move. Second collision of the particle with the wedge occurs at B. Find. (a) the length AB of the wedge(b) the normal reaction between the ground and the wedge during the first collision. [Given that angle theta = cot^(-1) (2)]

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ANSWER :(a) 1.8 m(B) 0.5 N


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