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A particle of mass 0.1 kg is subjected to a force which varies with distance as shown in figure. If it starts its journey from rest at `x=0`, its velocity at `x=12m` isA. `0(m)//(s)`B. `20sqrt2(m)//(s)`C. `20sqrt3(m)//(s)`D. `40(m)//(s)` |
Answer» Correct Answer - D `x=0` to `x=12m` `W=`area of F-x graph `=(1)/(2)(4+12)xx10=80J` `x=0`,`K_1=0` `W=K_2-K_1` `80=(1)/(2)mv^2-0=(1)/(2)xx0.1v^2` `v^2=1600impliesv=40(m)//(s)` |
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