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A particle of mass 0.10 kg executes SHM with an amplitude 0.05 m and frequency 20 vib/s. Its energy os oscillation isA. 2 JB. 4 JC. 1 JD. zero |
Answer» Correct Answer - A (a) `E=(1)/(2)momega^(2)A^(2)=(1)/(2)m(2pif)^(2)A^(2)=2pi^(2)f^(2)mA^(2)` `=2pi^(2)(20)^(2)(0.1)(0.05)^(2)=2 J" "` (approximately) |
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