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A particle of mass 0.75 kg is moving in the XY planeparallel to Y-axis with a uniform speed of 4m/s. Itcrosses the X-axis at 3m from the origin. What isthe angular momentum of the particle about theorigin? |
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Answer» Angular momentum(L) = m*v*rm= mass of the bodyv= velocityr= distance from the axis of rotation So, L =0.75 * 4 * 3 = 9kgm^2/s |
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