1.

A particle of mass 0.75 kg is moving in the XY planeparallel to Y-axis with a uniform speed of 4m/s. Itcrosses the X-axis at 3m from the origin. What isthe angular momentum of the particle about theorigin?

Answer»

Angular momentum(L) = m*v*rm= mass of the bodyv= velocityr= distance from the axis of rotation So, L =0.75 * 4 * 3 = 9kgm^2/s



Discussion

No Comment Found

Related InterviewSolutions