A particle of mass 1 mg has the same wavelength as an electron moving with a velocity of 3xx10^(6)ms^(-1). The velocity of the particle is (mass of electron =9.1xx10^(-31)kg)

A particle of mass 1 mg has the same wavelength as an electron moving

1.	A particle of mass 1 mg has the same wavelength as an electron moving with a velocity of 3xx10^(6)ms^(-1). The velocity of the particle is (mass of electron =9.1xx10^(-31)kg)
Answer» `2.7xx10^(-21)ms^(-1)` `2.7xx10^(-18)ms^(-1)` `9xx10^(-2)ms^(-1)` `3XX10^(-31)ms^(-1)` Solution :As per question `LAMDA=(h)/(mv)=(h)/(m_(e)v_(e))` `implies v=(m_(e)v_(e))/(m)=((9.1xx10^(-31)kg)(3xx10^(6)ms^(-1)))/((1MG))=(9.1xx10^(-31)xx3xx10^(6))/(1xx10^(-6))=2.7xx10^(-18)ms^(-1)`.

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A particle of mass 1 mg has the same wavelength as an electron moving with a velocity of 3xx10^(6)ms^(-1). The velocity of the particle is (mass of electron =9.1xx10^(-31)kg)

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