A particle of mass 100 g is thrown vertically upwards with a speed of

1.	A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. the work done by the forceof gravity during the time the particle goes up isAIEEE 2006, 1.5/180,-1]
Answer» M = 0.1 kgV1 = 5 m/sV2 = v1 - gt = 5 - 9.8 t = 0 (highest point)t = 0.51 sec S = v1 * t - 1/2gt^2 = 5 * 0.51 - 4.9 * (0.51)^2 = 1.276 m = h W = m * g * h = 0.1 kg * 9.8 m/s^2 * 1.276 m = 1.25 joulesor alternatively:W = initial Ek - final Ek = mgh = 1/2 m * V1^2 = 1.25 joules(final kinetic energy = 0, because of the work done by gravity, all Ek is transformed into potential energy Ep = mgh)

A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. the work done by the forceof gravity during the time the particle goes up isAIEEE 2006, 1.5/180,-1]

Answer»

M = 0.1 kgV1 = 5 m/sV2 = v1 - g*t = 5 - 9.8 * t = 0 (highest point)t = 0.51 sec

S = v1 * t - 1/2gt^2 = 5 * 0.51 - 4.9 * (0.51)^2 = 1.276 m = h

W = m * g * h = 0.1 kg * 9.8 m/s^2 * 1.276 m = 1.25 joulesor alternatively:W = initial Ek - final Ek = mgh = 1/2 m * V1^2 = 1.25 joules(final kinetic energy = 0, because of the work done by gravity, all Ek is transformed into potential energy Ep = mgh)

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A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. the work done by the forceof gravity during the time the particle goes up isAIEEE 2006, 1.5/180,-1]

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