A particle of mass 1kg is projected at an angle of theta=pi//4 from horizontal with a muzzle velocity of 20 m//s. A long slender rod of mass 5kg and length 30 m is suspended vertically from a point at the same horizontal leves as that of point of projection and at a distance of 60m from the projection point. The rod can rotate freely. If collision occurs, it is perfectly plastic. (g=10m//s^(2)) If the rod tilts to an angle theta after collision, then

A particle of mass 1kg is projected at an angle of theta=pi//4 from ho

1.	A particle of mass 1kg is projected at an angle of theta=pi//4 from horizontal with a muzzle velocity of 20 m//s. A long slender rod of mass 5kg and length 30 m is suspended vertically from a point at the same horizontal leves as that of point of projection and at a distance of 60m from the projection point. The rod can rotate freely. If collision occurs, it is perfectly plastic. (g=10m//s^(2)) If the rod tilts to an angle theta after collision, then
Answer» `theta=0^(@)` `theta=cos^(-1)(40//42)` `theta=cos^(-1)(41//42)` `theta=cos^(-1)(27//28)` Solution :HINT : FIRST find the point where collision OCCURS using equation of trajectory. Then USE conservation of angular MOMENTUM. After collision energy conservation is valid.

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