A particle of mass 1kg is projected at an angle of theta=pi//4 from horizontal with a muzzle velocity of 20 m//s. A long slender rod of mass 5kg and length 30 m is suspended vertically from a point at the same horizontal leves as that of point of projection and at a distance of 60m from the projection point. The rod can rotate freely. If collision occurs, it is perfectly plastic. (g=10m//s^(2)) Angular velocity of rod after collision is

A particle of mass 1kg is projected at an angle of theta=pi//4 from ho

1.	A particle of mass 1kg is projected at an angle of theta=pi//4 from horizontal with a muzzle velocity of 20 m//s. A long slender rod of mass 5kg and length 30 m is suspended vertically from a point at the same horizontal leves as that of point of projection and at a distance of 60m from the projection point. The rod can rotate freely. If collision occurs, it is perfectly plastic. (g=10m//s^(2)) Angular velocity of rod after collision is
Answer» `(1)/(4sqrt(2))rad//sec` `(4)/(SQRT(2))rad//sec` `4sqrt(2)rad//sec` zero Solution :HINT : First find the point where collision occurs using EQUATION of trajectory. Then use conservation of angular momentum. After collision energy conservation is valid.

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