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A particle of mass 2 is dropped from a height 80 m above the ground. At the same time another particle of mass m is thrown vertically upwards from the ground with a speed of 40 m/s. If they collide head-on completely inelastically, the time taken for the combined mass to reach the ground, in units of second is: |
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Answer» `((sqrt(112)-2)/(3))` at collision , `v_(A) = 20"" v_B = - 20` Velocity of combined mass `= (2 m XX 20-m xx 20)/(2m + m) = (20)/(3)` m/s Time taken by combined mass to rach the ground Time `=((sqrt(112)-2)/(3))` sec. 
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