1.

A particle of mass 200 g executes a simpel harmonit motion. The resrtoring force is provided by a spring of spring constant `80 N m^-1`. Find the time period.A. 0.93 sB. 0.63 sC. 0.31 sD. None of these

Answer» Correct Answer - C
(c) Time period , `T=2pisqrt((m)/(k))`
`impliesT=2xx3.14sqrt((200xx10^(-3))/(80))`
or, `T=2xx3.14sqrt((1)/(400))` or , `T=(2xx3.14)/(20)`
or, T=0.315


Discussion

No Comment Found

Related InterviewSolutions