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A particle of mass 200 g executes a simpel harmonit motion. The resrtoring force is provided by a spring of spring constant `80 N m^-1`. Find the time period.A. 0.93 sB. 0.63 sC. 0.31 sD. None of these |
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Answer» Correct Answer - C (c) Time period , `T=2pisqrt((m)/(k))` `impliesT=2xx3.14sqrt((200xx10^(-3))/(80))` or, `T=2xx3.14sqrt((1)/(400))` or , `T=(2xx3.14)/(20)` or, T=0.315 |
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