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A particle of mass m = 5 is moving with uniform speed v = 3sqrt(2) in the XOY plane along the line Y = X + 4. The magnitude of angular momentum of the particle about the origin is : |
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Answer» 60units The line of action of momentum is in XY PLANE given by the st. line y = x + 4. Comparing it with y = mx + c. The SLOPE of line tan `THETA` = 1 `:. theta` = 45° and the intercept of the line of y-axis is 4 units. Leng TH of the perpendicular distance 3 from the origin to the line of action of momentum is `z=4sin45^@=4/sqrt(2)` `=2sqrt(2)` units Moment of momentum or angular momentum is given by `L=mvz=15sqrt(2)xx2sqrt(2)=60` units  |
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