Saved Bookmarks
| 1. |
A particle of mass m = 5 units is moving with a uniform speed v = 3sqrt2 units in the XOY plane along the line Y = X + 4. The magnitude of the angular momentum of the particle about the origin is |
|
Answer» 60 units Y=X+ 4 line has been shown in the figure when x = 0,y = 4. So, OP = 4. The slope of the line can be obtained by comparing with the equation of line y=mx+c `rArrm=tantheta=1` `rArrtheta=45^(@)` `angleOQP=angleOPQ=45^(@)` If we draw a line perpendicular to this line. Length of the perpendicular= OR `rArrOR=OPsin45^(@)=4(1)/(SQRT2)=4/(sqrt2)=2SQRT2` Angular momentum of particle going ALONG this line `=rxxmv=2sqrt2xx5xx3sqrt2=60` units 
|
|