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A particle of mass m and change q enter the region between twocharged plates. The length of the plate is L and there is a uniform electric field 'E' between those plates as shown. Charge q enters into the field with an initial speed U as shown. Find the vertical deflection of the particle at the far edge of the plate? |
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Answer» Solution :Here charged particle EXPERIENCES force along vertical DIRECTION which is equal to EQ. As a RESULT its acceleration in the vertical direction is `(Eq)/(m)`. Along the horizontal direction, its velocity doesnot change. Time taken by the CHARGE to reach the other end of the plate is `t=(L)/(U)` During this time its vertical deflection is given by `y=(1)/(2) at^(2)` `y=(1)/(2) (Eq)/(m)((L)/(U))^(2) =(EqL^(2))/(2mU^(2))` |
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