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A particle of mass m and charge q has an initial velocity vecv =v_(0)hatj. If an electric field E = E_(0)hatiand B = B_(0)hatimagnetic field act on the particle, its speed will double after a time |
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Answer» `t=(sqrt(3)mv_(0))/(qE)`  Magnitude of VELOCITY doesn.t change in Y-Z plane. `(2v_(0))^(2) =v_(0)^(2) +v_(x)^(2)` `therefore v_(x) = sqrt(3)v_(0)` `therefore` From equation of motion, `v_(x) =v_(0x) + a_(0x)t` `therefore sqrt(3)v_(0) =(qE)/MT, therefore t=(sqrt(3)mv_(0))/(qE)` |
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