A particle of mass M and charge q , initially at rest , is accelerated by a uniform electric field E through a distance D and is then allowed to approach a fixed static charge Q of the same sign . The distance of the closest approach of the charge q will then be

A particle of mass M and charge q , initially at rest , is accelerated

1.	A particle of mass M and charge q , initially at rest , is accelerated by a uniform electric field E through a distance D and is then allowed to approach a fixed static charge Q of the same sign . The distance of the closest approach of the charge q will then be
Answer» `(Q)/(4piepsilon_(0)D)` `(Q)/(4piepsilon_(0)ED)` `(qQ)/(2piepsilon_(0)D^(2))` `(Q)/(4piepsilon_(0)E)` SOLUTION :Force acting on charge q is in uniform ELECTRIC field E is `threfore` WORK done on particle by electric field. W=qED. `thereforeQED=(1)/(4piepsilon_(0))rArrr_(0)=(Q)/(4piepsilon_(0)ED)`

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A particle of mass M and charge q , initially at rest , is accelerated by a uniform electric field E through a distance D and is then allowed to approach a fixed static charge Q of the same sign . The distance of the closest approach of the charge q will then be

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