Saved Bookmarks
| 1. |
A particle of mass M and charge q is released from rest in a region of uniform electric field of magnitude E . After a time t, the distance travelled by the chargeis S ad the kinetic energy attained by the particle is T. Then , the ratio T/S |
|
Answer» remains constant with time t `rArra=(qE)/(M)andv=(qE)/(M)t` Using , `S=ut+(1)/(2)at^(2)` `S=(1)/(2)((qE)/(M))t^(2)(becauseu=0)` Now , kinetic energy of particle, `T=(1)/(2)Mv^(2)=(1)/(2)M((qE)/(M)t)^(2) ""(becausea=(qE)/(M)t)` `therefore(T)/(S)=((1)/(2)M((qE)/(M))^(2)t^(2))/((1)/(2)((qE)/(M))t^(2))` `(T)/(S)=qE`. |
|