1.

A particle of mass m and charge q moves at high speed along the x-axis. It is initially near x = -oo and it ends up near x=+oo. A second charge is fixed at the point x = 0, y=-d. As the moving charge passes the stationary charge, its x component of velocity does not change appreciably, but it acquires a small velocity in y-direction. Determine the angle through which the moving charge is deflected

Answer»

`theta=tan^(-1)((QQ)/(2piepsilon_0dmv^2))`
`theta=sin^(-1)((qQ)/(2piepsilon_0dmv^2))`
`theta=tan^(-1)((qQ)/(4piepsilon_0dmv^2))`
`theta=sin^(-1)((qQ)/(4piepsilon_0dmv^2))`

ANSWER :A


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