A particle of mass `M` at rest dacays into two particle of masses `m_(1)` and `m_(2) `having non zero velocity . The ratio of the de Broglie wavelength . The ratio of the de Broglie wavelength of the particle `lambda , _(1) // lambda_(2)` isA. `(m_(1))/(m_(2))`B. `(m_(2))/(m_(1))`C. `1:1`D. `sqrt((m_(2))/(m_(1)))`

A particle of mass `M` at rest dacays into two particle of masses `m_(

1.	A particle of mass `M` at rest dacays into two particle of masses `m_(1)` and `m_(2) `having non zero velocity . The ratio of the de Broglie wavelength . The ratio of the de Broglie wavelength of the particle `lambda , _(1) // lambda_(2)` isA. `(m_(1))/(m_(2))`B. `(m_(2))/(m_(1))`C. `1:1`D. `sqrt((m_(2))/(m_(1)))`
Answer» Correct Answer - C `lambda=(h)/(p)` Since the momenta of the two particles are equal `lambda` are same.

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