InterviewSolution
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InterviewSolution
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A particle of mass m executes simple harmonic motion with amplitude a and frequency v. The average kinetic energy during its motion from the position of equilinrium to the end is.A. `pi^(2)ma^(2)epsi^(2)`B. `(1)/(4)ma^(2)epsi^(2)`C. `4pi^(2)ma^(2)epsi^(2)`D. `2pi^(2)ma^(2)epsi^(2)` |
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Answer» Correct Answer - A `K_(av)=(int_(0)^(T//4)(1)/(4)m[aomega cos(omegat)]^(2)dt)/(int_(0)^(T//4)dt)=(ma^(2)omega^(2))/(2(T)/(4))int_(0)^(T//4) cos^(2)(omegat)dt=(2ma^(2)omega^(2))/(T).(T)/(8)=(1)/(4)ma^(2)omega^(2)` `=(1)/(4)ma^(2)(2piepsi)^(2) , =pi^(ma^(2)epsi^(2)`. |
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