1.

A particle of mass m falls from a height h on a mass m and gets stuck to it. Then,

Answer»

<P>acceleration of the pulley - mass system after impact is given by g/5.
the height to which 3m mass RISES is h/5
the height to which 3m mass rises is h/3
acceleration of the pulley mass system after impact is g/3

Solution :`a=[(3m-(m+m))/(3m+(m+m))]g=g//5`
`P_(i)=m sqrt(2gh)`
`P_(i)=m sqrt(2gh)`
`P_(i)-l=P_(f)`
`m sqrt(2gh)-l=2mv`
`l = 3MV`
`v=(1)/(5)sqrt(2gh)`
`v^(2)=2gh.`
`h.=((1)/(5)sqrt(2gh))^(2)//(2G)/(5)=(h)/(5)`
`therefore`(A) & (B)


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