A particle of mass (m) is attached to a spring (of spring constant k) and has a narural angular frequency omega_(0). An external force `R(t)` proportional to cos omegat(omega!=omega)(0) is applied to the oscillator. The time displacement of the oscillator will be proprtional to.A. (a) `1/(m(omega_(0)^(2)+omega^(2))`B. (b) 1/(omega(omega_(0)^(2)-omega^(2))`C. (c ) `m/(omega_(0)^(2)-omega^(2)`D. (d) `m/(om_(0)^(2)+omega^(2))`

A particle of mass (m) is attached to a spring (of spring constant k)

1.	A particle of mass (m) is attached to a spring (of spring constant k) and has a narural angular frequency omega_(0). An external force `R(t)` proportional to cos omegat(omega!=omega)(0) is applied to the oscillator. The time displacement of the oscillator will be proprtional to.A. (a) `1/(m(omega_(0)^(2)+omega^(2))`B. (b) 1/(omega(omega_(0)^(2)-omega^(2))`C. (c ) `m/(omega_(0)^(2)-omega^(2)`D. (d) `m/(om_(0)^(2)+omega^(2))`
Answer» Correct Answer - B (b) Equation of desplacement is given by `x=A sin(omegat+phi) where `A=f_(0)/(m(omega_(0)^(2)-omega^(2)))`.

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