InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A particle of mass m is dropped from a great height h above the hole in the earth dug along its diameter.A. The motion of the particle is simple harmonicB. The motion of the particle is periodicC. The speed of the particle at the centre of earth equals `sqrt((2GM)/((R+h)))` , where R and M are the radius and mass of the earth respectivelyD. The speed of the particle at the centre of earth equals `sqrt((GM(R+3h))/(R(R+h)))`, where R and M are the radius and mass of the earth respectively |
|
Answer» Correct Answer - D (d) The motion is simple harmonic only inside earth. Further `(1)/(2) mv^(2)=-(GMm)/((R+h))+(3)/(2)(GMm)/(R)` `implies v=sqrt((GM(R-h))/(R(R+h)))` |
|