1.

A particle of mass m is executing oscillations about the origin on the x-axis, it's potential energy is U(x)=k|x|^(2), where k is apositive constant, if the amplitude of oscillation is a, then it's time period T is

Answer»

PROPORTIONAL `o(1)/(sqrt(a))`
INDEPENDENT of a
Proportional to `sqrt(a)`
Proportionalto `a^(3//2)`

SOLUTION :`because f(x,t_(0))=A sin.(x^(2))/(a^(2))""thereforef(x,t)=f(x-v(t-t_(0)),t_(0))=A sin .((x-v(t-t_(0)))^(2))/(a^(2))`


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