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A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration `a_(c)` is varying with time t as `a_(c) = k^(2)rt^(2)`, where k is a constant. The power delivered to the particle by the forces acting on it is :A. ` m^(2)K^(2)r^(2)t^(2)`B. `mK^(2)r^(2)t^(2)`C. `mK^(2)rt^(2)`D. `mKr^(2)t^(2)` |
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Answer» Correct Answer - B `F=ma=mK^(2)rt^(2)` `P=(w)/(t)=(F.s)/(t)=(mK^(2)rt^(2))/(t)r` `=mK^(2)r^(2)t` |
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