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A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to `(-K//r^(2))`, where k is a constant. The total energy of the particle is -A. `-K//r`B. `-K//2r`C. `K//2r`D. `-2K//r` |
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Answer» Correct Answer - B `F=(-K)/(r^(2))` `KE=(1)/(2)Fr=(1)/(2)(-K)/(r^(2))xxr=-(k)/(2r)` |
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