1.

A particle of mass `m` is released from rest at point `A` in Fig., falling parallel to the (vertical) `y`-axis. Find the angular momentum of the particle at any time `t` with respect to the same origin `O`.

Answer» `vecL=vecrxxvecp`
The magnitude of `vecL` is given by `L=rp sintheta(hatk)`
in this example velocity of the particle at any time
`v="gt",rsintheta=x_(0)` and `p=mv=m"gt"`
`:.vecL=mgx_(0)t(hatk)`……..i
The right hand rule shows that `vecL` is parallel to torque, i.e. direcrected perpedicular to paper in wards.


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