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A particle of mass `m` moves in a circle of radius `R` with a uniform speed `v`. (i) the angular speed of particle is `v//R`. (ii) the time period of revolution is `2piR//v`. (iii) the acceleration of particle is `v^(2)//R`. (iv) the work done by the centripetal force in half revolution is `(mv^(2)//R)xxpiR`.A. `(i),(ii)`B. `(ii),(iii)`C. `(ii),(ii),(iii)`D. All options are correct |
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Answer» Correct Answer - C The work done by the centriple force is always zero. |
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