InterviewSolution
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InterviewSolution
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A particle of mass m moves in a circle of radius R in such a way that its speed `(v)` varies with distance (s) as `v = a sqrt(s)` where a is a constant. Calcualte the acceleration and force on the particle.A. `a^(2)sqrt((1)/(4)-(S^(2))/(R^(2)))`B. `a^(2)sqrt((1)/(4)+(S^(2))/(R^(2)))`C. `asqrt((1)/(2)+(S^(2))/(R^(2)))`D. `a^(2)sqrt((1)/(2)+(S^(2))/(R^(2)))` |
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Answer» Correct Answer - b `a=sqrt(a_(1)^(2)+a_(1)^(2))` `=sqrt(((dv)/(dt))^(2)+((v^(2))/(R))^(2))` |
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