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A particle of mass m rotating in a plane circular path of radius r has angular momentum L. The centripetal force acting on its is :

Answer»

`(L^(2))/(mr)`
`(L^(2)m)/(r^(2))`
`(L^(2))/(mr^(3))`
`[(L)/(mr)]^(1//2)`

Solution :Centripetal force, `F_(C)=(mv^(2))/(r)` and angular momentum `L=mvr`
`F_(C)=(m^(2)V^(2))/(mr)""(because mv=(L)/(r))`
`therefore F_(C)=(L^(2))/(mr^(2).r)=(L^(2))/(mr^(3))`


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