A particle of mass m strikes a wall normally with a velocity v and then its velocity reversed. The change in momentum is :

A particle of mass m strikes a wall normally with a velocity v and the

1.	A particle of mass m strikes a wall normally with a velocity v and then its velocity reversed. The change in momentum is :
Answer» <P>m`UPSILON` 2m`upsilon` zero - 2m`upsilon` SOLUTION :`Deltap=vecp_(2)-p_(1)=-vec(m upsilon)-vec((m upsilon))=-2vec((m upsilon))` Hence correct choice is (d).

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A particle of mass m strikes a wall normally with a velocity v and then its velocity reversed. The change in momentum is :

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