A particle of mass m1 is moving with a velocity `v_(1)` and another particle of mass `m_(2)` is moving with a velocity v2. Both of them have the same momentum but their different kinetic energies are E1 and E2 respectively. If `m_(1) gt m_(2)` thenA. `E_1/E_2=m_1/m_2`B. `E_1 gt E_2`C. `E_1=E_2`D. `E_1 lt E_2`

A particle of mass m1 is moving with a velocity `v_(1)` and another pa

1.	A particle of mass m1 is moving with a velocity `v_(1)` and another particle of mass `m_(2)` is moving with a velocity v2. Both of them have the same momentum but their different kinetic energies are E1 and E2 respectively. If `m_(1) gt m_(2)` thenA. `E_1/E_2=m_1/m_2`B. `E_1 gt E_2`C. `E_1=E_2`D. `E_1 lt E_2`
Answer» Correct Answer - D `because E=rho^2/"2m"therefore Eprop 1/m` if `m_1 gt m_2` then ` E_1 lt E_2`

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