A particle of mass mis dropped from a height habove the ground. At the same time another particle of mass 2m is thrown vertically upwards from the ground with a speed of sqrt(gh) . If they collide head-on completely inelastically, the time taken for the combined mass to reach the ground, in units of sqrt(h/g)is:

A particle of mass mis dropped from a height habove the ground. At the

1.	A particle of mass mis dropped from a height habove the ground. At the same time another particle of mass 2m is thrown vertically upwards from the ground with a speed of sqrt(gh) . If they collide head-on completely inelastically, the time taken for the combined mass to reach the ground, in units of sqrt(h/g)is:
Answer» `(sqrt40 -2)/6` `(sqrt(30)-3)/7` `(sqrt(20)-2)/5` `sqrt(3/2)` Solution : Particles will collide after time `t_0 h/sqrt(GH)` at collision, `v_A= -g sqrt(h//g), V_B = 0` Time taken by COMBINED MASS to reach the ground Time `= ((sqrt(40)-2)/6)sqrt(h//g)`

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