A particle of mass W is projected with a velocity V making an angle of 30° with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height H is:

A particle of mass W is projected with a velocity V making an angle of

1.	A particle of mass W is projected with a velocity V making an angle of 30° with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height H is:
Answer» zero `(MV^(2))/(SQRT(2)G)` `(sqrt(3)mv^(3))/(16g)` `(sqrt(3)mv^(3))/(2g)` Solution :Here the angular momentain ‘L’ is given by `L=pr=mvcostheta.H` `=mvcos30^@xx(v^(2)sin^(2)30^@)/(2g)` `mv^(3)xxsqrt(3)/2XX1/(4xx2g)=(sqrt(3)mv^(3))/(16g)`

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A particle of mass W is projected with a velocity V making an angle of 30° with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height H is:

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