A particle of massmis dropped from a heighth above the ground. At the same time another particle of mass 2m is thrown vertically upwards from the ground with a speed ofsqrt(gh) . If they collide head-on completely inelastically, the time taken for the combined mass to reach the ground, in units of sqrt(h/g) is :

A particle of massmis dropped from a heighth above the ground. At the

1.	A particle of massmis dropped from a heighth above the ground. At the same time another particle of mass 2m is thrown vertically upwards from the ground with a speed ofsqrt(gh) . If they collide head-on completely inelastically, the time taken for the combined mass to reach the ground, in units of sqrt(h/g) is :
Answer» `(sqrt40-2)/6` `(sqrt30-3)/7` `(sqrt20-2)/5` `sqrt(3/2)` Solution : Particles will collide after time `t_0 = (h)/(sqrt(gh)) ` at collision ,`v_A = "GT"_0 ""v_B = u_B - "gt"_0` `implies v_A = - gsqrt(h//g), v_B = 0 ` Time TAKEN by combined mass to REACH the ground Time `= ((sqrt(40)-2)/(6)) sqrt(h//g)`

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