1.

A particle of specific charge alpha starts moving from (0,0,0) under the action of electric field E = chati and magnetic field vecB = B_(0)hatk. Its velocity at (x, 0, 0) is 4hati + 3hatj. Find the value of x

Answer»

SOLUTION :`1/2mv^(2)=vecF.vecS,1/2m(25)=Q(vecE.vecS)`
`25/2=alpha(ehati.xhati),exalpha=25/2x=25/(2alphae)`


Discussion

No Comment Found

Related InterviewSolutions