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A particle of specific charge alpha starts moving from (0,0,0) under the action of electric field E = chati and magnetic field vecB = B_(0)hatk. Its velocity at (x, 0, 0) is 4hati + 3hatj. Find the value of x |
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Answer» SOLUTION :`1/2mv^(2)=vecF.vecS,1/2m(25)=Q(vecE.vecS)` `25/2=alpha(ehati.xhati),exalpha=25/2x=25/(2alphae)` |
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