1.

A particle performing linear S.H.M. has a period 2pi seconds and an amplitude of 10 cm. What is its velocity when its displacement is 6 cm from the mean position ?

Answer»

SOLUTION :`v=omegasqrt(a^2-x^2)=(2PI)/Tsqrt(a^2-x^2)`
`=(2pi)/(2pi)SQRT(10^2-6^2)=8=8 cm//s`


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